Question

a square + b square + c square minus 2 a b + 2 BC - 2 AC

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Answer 1

Answer:

QUESTION IS INAPPROPRIATE

Answer 2

Answer:

$\frac{1}{2}$(2a²+2b²+2c²-4ab-4bc-4ca)

=$\frac{1}{2}$(a²+b²-2ab+b²+c²-2bc+c²+a²-2ac)

=$\frac{1}{2\\}$[(a-b)²+(b-c)²+(c-a)²]