Question

A square + b square + c square minus a b minus b c minus c is equals to zero then find a prove equals to b equals to c

Answer 1

Answer:

Consider a^2+b^2+c^2-ab-bc-ca=0

Multiply on both sides with 2, we get

2(a^2+b^2+c^2-ab-bc-ca)=0

2a^2+2b^2+2c^2-2ab-2bc-2ca=0

(a^2-2ab-b^2)+(b^2-2bc+c^2)+(c^2-2ca+a^2)=0

(a-b)^2+(b-c)^2+(c-a)^2=0

Since the sum of square is zero then each term should be zero

(a-b)^2=0 , (b-c)^2=0 , (c-a)^2=0

(a-b)=0 , (b-c)=0 , (c-a)=0

a=b ,b=c ,c=a

Therefore, a=b=c

Hope u understand

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Answer 2

Answer:

Here is ur Answer mate.....