Question

A square coil 10⁻² m² area is placed perpendicular to a uniform magnetic field of intensity 10³Wb / m². The magnetic flux through the coil is
(a) 10 weber(b) 10⁻⁵ weber(c) 10⁵ weber(d) 100 weber

Answer 1

answer : option (a) 10 Wb

explanation : cross sectional area of square coil, A = 10^-2 m²

magnetic field intensity, B = 10³ Wb/m²

the magnetic flux through the coil, $\phi=\vec{B}.\vec{A}$

= $BAcos\theta$

a/c to question, magnetic field is perpendicular to square coil so, angle between area vector and magnetic field vector, $\theta$ = 0°

hence, magnetic flux through the coil = 10³ × 10^-2 × cos0°

= 10 Wb

hence , option (a) is correct