Question

A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force onone arm of the loop is $\vec{F}$, the net force on the remaining three arms of the loop is(a) $3\vec{F}$(b) $-\vec{F}$(c) $-3\vec{F}$(d) $\vec{F}$

Answer 1

Net force on the remaining three arms of the loop will be (b) -F

Let ABCD is a square loop carrying current placed in a uniform magnetic field,

Due to this field the conductors of the loop will experience force.

The direction and magnitude of the force is directly proportional to the current carried in the conductor.

Given,

Force in one arm AB = F

since opposite branches of this loop carry current in opposite direction

=> force in the opposite arm CD = -F

Similarly The force in in the branches AD and BC will be opposite in direction and cancel out when added.

Hence net force on the remaining three arms of the loop will be (b) -F

Answer 2

Explanation:

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