Question

The magnetic field (dB) due to small element (dl) at a distance ($\vec{r}$) from element carrying current i, is
(a) dB = $\frac{\mu_{0}}{4\pi}i\bigg \lgroup \frac{\vec{dl}\times\vec{r}}{r}\bigg \rgroup$(b) dB = $\frac{\mu_{0}}{4\pi}i^{2}\bigg \lgroup \frac{\vec{dl}\times\vec{r}}{r}\bigg \rgroup$
(c) dB = $\frac{\mu_{0}}{4\pi}i^{2}\bigg \lgroup \frac{\vec{dl}\times\vec{r}}{r^{2}}]\bigg \rgroup$(d) dB = $\frac{\mu_{0}}{4\pi}i\bigg \lgroup \frac{\vec{dl}\times\vec{r}}{r^{3}}\bigg \rgroup$

Answer 1

HERE IS YOUR ANSWER :-

Option No. D

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