Question

A square field has each side 70cm where as a rectangular field has a length 50cm and breadth 40cm Which of the two field has greater by perimeter and how by much

Answer 1

Answer:

Perimeter of the Square is greater than the Perimeter of the rectangle by 100 cm.

Step-by-step explanation:

Given :

Side of the Square = 70 cm

Rectangular fields length = 50 cm

Breadth = 40 cm

To find :

Which fields Perimeter is greater and by how much

Solution :

★ Perimeter of the Square -

$\implies$ Side × 4

$\implies$ 70 × 4

$\implies$ 280 cm

$\rule{300}{1.5}$

★ Perimeter of the Rectangle -

$\implies$ 2(Length + Breadth)

$\implies$ 2(50 + 40)

$\implies$ 2(90)

$\implies$ 180 cm

$\rule{300}{1.5}$

The Perimeter of the Square is greater than the Perimeter of the Rectangle.

$\implies$ 280 - 180

$\implies$ 100

$\therefore$ Perimeter of the Square is greater than the Perimeter of the rectangle by 100 cm.

Answer 2

$\bf{\underline{\underline{Answer:}}}$

• Square field is greater than rectangular field by 100 cm

$\bold{\underline {Given:}}$

• A square field has each side 70cm.

• A rectangular field has a length 50cm and breadth 40cm.

$\bold{\underline {To\:find:}}$

• Which of the two field has greater by perimeter and how by much.

$\bf{\underline{\underline{Step\: by\: step \:explanation:}}}$

Firstly we will find the perimeter of square,

$\bigstar{\boxed{ \bf Perimeter\: of \:square = 4 \times side}}\\ \\ \tt Side\: of \:square = 70\: cm\\ \\ \tt \implies 4\times 70\\ \\ \tt \implies 280 cm.$

Now we will find the perimeter of rectangle,

$\bigstar{\boxed{\bf Perimeter\: of \:rectangle = 2(l + b)}} \\ \\ \tt Length \:of \:rectangle = 50\: cm\\ \\ \tt Breadth = 40\:cm\\ \\ \tt So, \\ \\\tt \implies 2(50+ 40)\\ \\ \tt \implies 2\times 90\\ \\ \tt \implies 180 cm.$

So, perimeter of square is greater than the perimeter of rectangle,

= Perimeter of square - Perimeter of rectangle

= 280 - 180

= 100 cm

Thus, Perimeter of square is greater than the perimeter of rectangle by 100 cm.