a square field of area 31684 m2 is to be enclosed with the wire placed at height 1 m, 2 m, 3 m, 4 m above the ground. what length of the wire will be required if its length required for each circuit is 5% greater than the perimeter of the field?
Answers
Answer:
Total length of wire is 2990.4 m
Step-by-step explanation:
Given that a square field is to be enclosed by four wires at height 1m, 2m, 3m and 4m.
Area of square field = 31684 m²
Let's find the perimeter of square
As we know
Area of square = x²
So,
x² = 31684 m²
taking square root on both sides
√x² = √31684 m²
x = 178 m
So, the length of one side of square is x = 178 m
As we know the perimeter of the square is calculated as
P = 4x
P = 4x178
P = 712 m
Given that length of wire for each circuit is 5% more than the length of perimeter of square. So,
Length of wire = Length of perimeter + 5% of Length of perimeter
l = 712 + 0.05x712
l = 712 + 35.6
l =747.6 m
As we need to enclose the square field by wires four times at different height; therefore,
Total Length of wire = 4l
Total Length of wire = 4x 747.6
Total Length of wire = 2990.4 m
So, total length of wire is 2990.4 m
Answer:
Step-by-step explanation:
Ans: 2990.4 m
Solution: let a is side of square field then a2=31684
a=178
perimeter= 4 * a = 712
5% more than perimeter = 712 + 5% of 712 = 712 + 35.6 = 747.6
Because we enclose four times so 4 * 747.6 = 2990.4