Question

. A square floor of side 30 m is to be tiled with right triangles of sides
3 m and 4 m. How many tiles will be needed to cover the floor?
​

Answer 1

Step-by-step explanation:

Area of square floor = Side×Side= 30×30=900m²

area of tile= 1/2 × Base× Height= 1/2 × 3 × 4 = 6m²

∴

No. of tiles required = Area of square floor/ Area of tile= 900/6 =150 Tiles

Answer 2

Answer:

150 tiles are needed to cover the floor.

Explanation:

Given: The side length of the square floor is 30m.

           It is to be tiled with right triangles.

           The side lengths of each right triangle are 3m and 4m.

To find: The number of tiles that would be required to cover the floor.

Steps to be done while solving:

1. Write the given measurements of the square and the right triangle.
2. Use the area of the square formula.
3. Find the area of the square floor.
4. Use the area of the triangle formula.
5. Find the area of each right-angled triangle.
6. Then, divide the area of the square by the area of each triangle.
7. Find the required number of tiles.

Formulae to be used:

The area of a square with the side length a is given by,

$A=a^{2}$

The area of the triangle with base b and height h is given by,

$A=\frac{1}{2} \times b\times h$

Step 1 of 3:

Considering the square floor:

Given the side length,

$a=30m$

The area of the square floor is,

$A=30^{2}\\ =900m^{2}$

Step 2 of 3:

Considering the right-angled triangular tile:

Assuming one as the base and another as the height,

$b=3m\\h=4m$

The area of the right-triangled tile is,

$A=\frac{1}{2}\times 3 \times 4\\=3 \times 2\\=6m^{2}$

Step 3 of 3:

Dividing the area of the square floor by the area of a triangular tile,

$\frac{Area \; of \;square}{Area\; of \; triangle} =\frac{900m^{2} }{6m^{2} } \\=150$

Final answer:

Hence, the required number of tiles is 150.