A square has 98 sq cm area. What will be area of circle passing through its vertices .
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Area of a sphere is related to it's sides as
s^2 = A
Thus s = ✓98 = 7✓2 cm
Now when you imagine a circle passing through a square's vertices, you will find that the circle's diameter is the same as the square's diagonal.
Thus length of diagonal of a square
d = s×✓2 = 14 cm
Thus the diameter is 14cm. Hence the radius is 7cm.
Thus area of the circle =
πr^2 = 3.14×49 = 153.86 sq cm
s^2 = A
Thus s = ✓98 = 7✓2 cm
Now when you imagine a circle passing through a square's vertices, you will find that the circle's diameter is the same as the square's diagonal.
Thus length of diagonal of a square
d = s×✓2 = 14 cm
Thus the diameter is 14cm. Hence the radius is 7cm.
Thus area of the circle =
πr^2 = 3.14×49 = 153.86 sq cm
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1
let side length be l
l2 = 98
l=root 98
The circle passing through the vertices will have its diameter along the diagonal of the square
Therefore diagonal = l root2 = root 98*2 = 14
Now area of circle = pie d^2 / 4
= 3.14 * 14*14/4
= 153.86
l2 = 98
l=root 98
The circle passing through the vertices will have its diameter along the diagonal of the square
Therefore diagonal = l root2 = root 98*2 = 14
Now area of circle = pie d^2 / 4
= 3.14 * 14*14/4
= 153.86
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