a square has a side of 5 cm find the length of one of its diagonals
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5.........................cm
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as we know that the square 90 angle at its vertex
then, by pythagoras thoerem,
5^2 +5^2 = diagonal^2
25+25= diagonal^2
50 = diagonal^2
2*(root5) = diagonal
i hope this will help you
- by ABHAY
then, by pythagoras thoerem,
5^2 +5^2 = diagonal^2
25+25= diagonal^2
50 = diagonal^2
2*(root5) = diagonal
i hope this will help you
- by ABHAY
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