A square has diagonals of length 10 cm. Find the sides of the square.
Answers
Answer :-
◍ The side of the square is 5√2 cm.
Given :-
✧ Length of the diagonal = 10cm
To find :-
・The side of the square
Concept Using :-
Pythagoras Theorem,
→ In a right angled triangle the square of hypotenuse is equal to the sum of square of base and perpendicular.
Solution :-
Diagram of the solution is in the attachment.
In the diagram,
AB = Side of the square = S
AC = Diagonals of the square = Hypothenuse
As, we know that all sides of a square are equal. Therefore, BC = AB = S
→ In right angled ∆ABC,
Using Pythagoras Theorem,
=> (AC)² = (AB)² + (BC)²
=> (10cm)² = (S)² + (S)²
=> 100cm² = S² + S²
=> 100cm² = 2S²
The length of the side = 5√2 cm
More Information :-
◍ Perimeter of the square = 4 × square
◍ Area of the rectangle = Length × Breadth
◍ Perimeter of the rectangle = 2(Length + Breadth)
◍ Area of circle = π × (radius)²
◍ Circumference of the circle = 2 × π × radius
Answer:
Question⤵
➡A square has diagonals of length 10 cm. Find the sides of the square.
Answer⤵
➡The side of square is 5√2.
Given⤵
➡Length of diagonal =10cm.
To find ⤵
➡The side of the square.
Concept using ⤵
➡Pythagoras theorem,
In a right angled triangle the square of hypotenuse is equal to the sum of the square of base and perpendicular.
Hypotenuse²=Base²+Perpendicular²
Solution⤵
In the diagram(diagram of the solution in attached pic)
AB=Side of the square=S
AC = Diagonal of the square=Hypotenuse
As , we know that all sides of a square is equal,
therefore AB = BC =S
➡In a right angled ∆ABC
Using Pythagoras theorem,
=> (AC) ²=(AB) ²+(BC) ²
=> (10cm) ²=(S) ²+(S) ²
=>100cm²=S²+S²
=> 100cm²=2S²
=> 100/2cm²=S²
=>50cm²=S²
=> √50cm²= S
=> 5√2 =S
The length of side=5√2cm
More information ⤵
➡Perimeter of square=4×Side
➡Area of square= Side² or Side ×Side
➡Perimeter of rectangle=2(Length+Breath)
➡Area of rectangle= Length× Breath
Hope this is helpful to you!