Question

a square has each sides of 5cm .find the length of one of its diagonals

Answer 1

Let's solve using Pythagoras theorem!

We know that two sides of any square along with its diagonal makes a right angled triangle so we can apply Pythagoras theorem here.

Since in our triangle two sides are of square, they both will measure 5 cm.

Now we have to calculate the length of hypotenuse i.e. the diagonal.

By Pythagoras theorem,
hypotenuse^2 = perpendicular^2 + base^2
h^2 = 5^2 + 5^2
h^2 = 25 + 25
h^2 = 50
h = √50
h = √2*5*5
h = 5√2 cm

Therefore,
The measure of the diagonal = 5√2 cm

Answer 2

☺☺☺☺hello dude it's very easy but it's answer in logic here..........


By pythagoras theorem (since two adjacent sides enclose an angle of 90°),
(5)² + (5)² = (Diagonal)²
⇒ 25 + 25 = (Diagonal)²
⇒ 50 = (Diagonal)²
⇒ Diagonal = √50
⇒ Diagonal = 5√2 cm.