A square has sides 5s 1 2 4 yards long. A rectangle is (s 1 9) yards long and (3s 5) yards wide. a) Find the perimeter of the square. b) Find the perimeter of the rectangle. c) Find the sum of the perimeters of the two figures if s 5 5. d) The perimeter of the rectangle is greater than the perimeter of the square. Find the difference between the perimeters of the two figures if s 5 7.
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5s + 2 Yards , 8s + 8 Yards , 13s + 10 Yards , 75 Yards , 3s + 6 Yards , 27 Yards
Step-by-step explanation:
A square has sides = (5s + 2)/4 Yards
Perimeter of Square = 4 * Side
= 4 * (5s + 2)/4
= 5s + 2 Yards
Sides of rectangle = (s + 9) & (3s - 5 ) yards
Perimeter of ractnagle = 2 ( s + 9 + 3s - 5)
= 8s + 8 Yards
Sum of both perimeters = 5s +2 + 8s + 8
= 13s + 10 Yards
if s = 5
then 13*5 + 12 = 75 Yards
Difference
8s + 8 - (5s + 2)
= 3s + 6 Yards
s = 7
3 * 7 + 6 = 27 Yards
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