Question

a square has the perimeter 56 m. find its area the length of one diagonal correct up to two decimal places.​

Answer 1

Answer:

perimeter of square=4a=56

a=56/4=14m

area of square =a^2=(14)^2=196m^2

diagonal of square=a√2=14×√2=19.798m

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Perimeter:

$\implies$ $P=4l$

$\implies$ $56=4l$

$\implies$ $l=\Large\frac{56}{4}$

$\implies$ $\boxed{l=14\:m}$

Area:

$\implies$ $A=l^{2}$

$\implies$ $A=14^{2}$

$\implies$ $\boxed{A=196\:m^{2}}$

As you know square forms a right angle at vertex, Find Diagonal using Pythagorous theorem :

$\implies$ $H^{2}=P^{2}+b^{2}$

$\implies$ $H^{2}=14^{2}+14^{2}$

$\implies$ $H=\sqrt{392}$

$\implies$ $\boxed{H=19.79\:m}$

Diagonal length = 19.79m

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