A square is inscribed in a circle, the circle has radius 4. Perimeter
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Solution :
It is given that ,
A square is inscribed in a
circle .
Let side of a square = a
diagonal = d
radius of the circle = r = 4
d = 2r
=> √2a = 2r
=> a = ( 2 × 4 )/√2
=> a = ( √2 × √2 × 4 )/√2
=> a = 4√2
Perimeter ( P ) = 4a
= 4 × 4√2
= 16√2
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