Question

A square is inscribed in the circle x² + y^2

- 10x - 6y + 30 = 0. One side of the square is
parallel to the straight line y = x + 3. Then one of the vertices of the square is
(A) (3, 3)
(B) (7,3)
(C) 5, 5)
(D) (9,5)
​

Answer 1

the answer of this question is A 3,3