Question

A square loop of resistance 11 ohms having area 0.15m2 placed in magnetic field of 2t

Answer 1

The velocity is v = 1.6×10^-4 m/s  

Explanation:

Given data:

• Resistance of loop = 11 ohm
• Area of loop = 0.15 m^2
• Magnetic field B = 2 t

Solution:        

 e = B.v.l = 2 ×  v × 2π × 0.15   ----- (1)

 e = I.R = 2 × 10^-3 × 1   ------ (2)

As equation (1) and (2) are same therefore

2 × v × 2π × 0.15 = 2 × 10^-3 × 1

or v  = 2 × 10^-3 × 12 × 2π × 0.15

= 10^-32 × 3.14  

v = 1.6×10^-4 m/s    

Thus the velocity is v = 1.6×10^-4 m/s

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