A square loop of wire with an area of 2.5x10-3 m2 is perpendicular to a uniform magnetic field (B = 2.2x10-2 T). If the square collapsed to an area of essentially 0 m2 in a time of 0.100 s as shown in the diagram what is the average induced emf as it is collapsed and what is the direction of the induced current? (Remember to use conventional current)
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Answer:Area = 2.5×10
−3
Side of square = a=0.05m
The frame is pulled out in 1 s
Velocity =
dt
dx
=
1s
a
=0.05m/s
By faraday's law
ϵ=−
dt
dϕ
=−
dt
dN(2.5×10
−3
)0.4
=0.1V
Resistance = 100 Ω
Work done =
R
ϵ
2
=0.1mJ
Explanation:
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