A SQUARE OF DIAGONAL 8cm is inscribed in a circle. find the ratio of areas of the circle to the ratio of the area of square
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Length of diagonal of the square= √2*side
8 cm = √2*side
8/√2 = side
. '. Side of the square= 8/√2
Diameter of the circle=length of diagonal of the square = 8 cm
. '. Radius of the circle = 8/2
= 4cm
Ratio of areas of the circle to the ratio of the area of square
. '. Area of a circle : area of the square
πr² : (side)²
22/7*4*4: 8/√2*8/√2
352/7: 64/2
352/7: 32
11/7: 1
. '. 11 : 7
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