Question

A square of side 3 cm is placed 25 CM away from a convex mirror of focal length 10 cm what is the area enclosed by image of the wire the centre of the wire is on the axis of the mirror with the two side normal to the access

Answer 1

So, now magnification m = height of the image / height of the object which is given as m=-v/u or -(-50/3)/-25 = height of the image/3 Which on solving we will get the height of the image as -2 cm. So, the area will be (-2)^2 which is 4 cm^2.