Question

A square of side 3cm is placed at a distance of 25cm from a concave mirror of focal length 10cm. The centre of the square is on the axis of the mirror and the plane is normal to the axis. The area enclosed by the image of the square is

Answer 1

Answer:

4 cm^2.

Explanation:

From the lense formulae we have that the 1/f=1/v-1/u. Where f is the focal length of the lense, v is the object distance and u is the image distance.

So, on substituting the values in the equation we will get that 1/v=-1/10-1/(-25) which on solving we will get the value of v=-50/3 cm.

So, now magnification m = height of the image / height of the object which is given as m=-v/u or -(-50/3)/-25 = height of the image/3 Which on solving we will get the height of the image as -2 cm. So, the area will be (-2)^2 which is 4 cm^2.

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