Question

a square of side 4 cm and uniform thickness is divided into four equal squares if one square is cut off find the position of the centre of mass remaining position from
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Answer 1

The position of the centre of mass is at 1/3×√2 cm

Explanation:

Let m be the mass of each small square. Therefore, total mass of given square = 4 m. This acts at the centre O of the square. Let O1 be cm of the cut off square (shown shaded) of mass m and O2 be cm of the remaining square of mass 3 m.

Now, AC= √AB^2+BC^2

=√4^2+4^2 = 4√2 cm

OC = 1/2 AC = 4√2/2 = 2√2 cm

OO1 = 1/2 = √2 cm

Now, moment of unshaded portion of mass (3m) aboutO= moment of shaded portion of mass (m) about O.

∴3 m×OO2 = m×OO1

OO2 = 1/3(OO1) = 1/3×√2 cm

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Answer 2

Explanation:

Here is your answer

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