Question

a square of side 6 cm is given find how many square of Side 2 cm are required to cover it

Answer 1

Side of square = 6cm

Area of square=6×6=36 cm²

Area of small square=2 cm

Area of small square=2 × 2=4 cm²

Number of square required to cover it=$\frac{Area of bigger square}{Area of smaller square}$

=36/4=9

9 squares are required.

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Answer 2

Given:

A square of side 6 cm is given

To Find:

find how many square of Side 2 cm are required to cover it

Solution:

Side of large square = 6 cm  

Area of large square =$Side^2 = 6^2 = 36 sq.cm.$

Side of small square = 2 cm  

Area of small square = $Side^2 = 2^2 = 4 sq.m.$

No. of squares required =   $\frac{36}{4}=9$

Hence 9 square of Side 2 cm are required to cover it