Question

A square park has each of 25m at each corners there is a flower bed in the form of sector in radius 3.5cm.find the area of the remaning park.

Answer 1

Area of the square = 25² = 625 m²


Now the flower bed are in the form of sector. We know that the corners are of 90° in a square.

Area of sector = ∅/360 × πr²

Where, ∅ = angle

=> area of sector = 90/360 × πr²

= area of sector = 1/4 × πr²

Now since there are four sectors and their area will be equal as the radius is equal.

So total area of sectors = 4 × 1/4 × πr²

=> πr²

=> 22/7 × 3.5 × 3.5

= 22 × 0.5 × 3.5

= 38.5 m²

So remaining area = area of square - total area of sectors

= 625 - 38.5

= 586.5 m²

Answer 2

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$\bold{Dear \:user!!}$


$\bold{\underline{Question-}}$A square park has each of 25m at each corners there is a flower bed in the form of sector in radius 3.5cm.find the area of the remaning park.

$\bold{\underline{Answer-}}$ According to the question we know that A square park has each of 25m at each corner there is a flower bed in the form of sector in radius 3.5cm .we know that corners are of 90° of square

Now, area of square is 625 m²

Area of sector is $\frac{ \theta}{360} \times \pi {r}^{2}$

$= \frac{90}{360} \times \pi {r}^{2}$

$\frac{1}{4} \times \pi {r}^{2}$

now, the total area of sector is$4 \times \frac{1}{4} \pi {r}^{2}$ = πr²

$= > \frac{22}{7} \times 3.5 \times 3.5$

$= > 38.5 {m}^{2}$

Then, remaining area is Area of square - Area of sector

now, 625 - 38.5

=> 586.5 m²