A square piece of paper of side 12 cm is rolled to form a cylinder. find its C.S.A
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Answered by
0
side forms its circumference.
2Πr^2=12
r^2=42÷11
r=√3•81
r=1•95
CSA=2Πrh
=2×22÷7×1•95×12
=147•09
2Πr^2=12
r^2=42÷11
r=√3•81
r=1•95
CSA=2Πrh
=2×22÷7×1•95×12
=147•09
Answered by
1
since the cylinder is made of square paper so
CAS of cylinder = area of sqaure sized paper
=12*12
=144 cm. sq.
CAS of cylinder = area of sqaure sized paper
=12*12
=144 cm. sq.
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