A square piece of paper of side 12cm is rolled to form a cylinder and find the curved surface area of the cylinder
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In the given question,
Side of a square = 12
Now, when this square paper is rolled to form a cylinder;
Height (h) = 12 cm
Now, let the base radius be r. So,
Side of a square=circumference of the base of the cylinder12=2πrr=122πr=6π
Next, we know that the curved surface area of the cylinder is given by;
CSA=2πrhCSA=2π(6π)12CSA=144
Therefore, the curved surface area of the cylinder is given by 144 cm2
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Side of a square = 12
Now, when this square paper is rolled to form a cylinder;
Height (h) = 12 cm
Now, let the base radius be r. So,
Side of a square=circumference of the base of the cylinder12=2πrr=122πr=6π
Next, we know that the curved surface area of the cylinder is given by;
CSA=2πrhCSA=2π(6π)12CSA=144
Therefore, the curved surface area of the cylinder is given by 144 cm2
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Csa.cyl. = 2πrh
circumstances.=side
2πr= 12cm
h. = side
h = 12
csa.cylinder = 12*12
csa.cylinder = 144
circumstances.=side
2πr= 12cm
h. = side
h = 12
csa.cylinder = 12*12
csa.cylinder = 144
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