a square plot has a 3 m wide path surrounding it. if the area of the path is 132 sq m. find the area of the plot.
Answers
Answered by
104
Let the side of the square plot be x m
Let the side of the square plot including the path be x' m
x' can be calculated by adding width of the path
Thus, x' = x+3+3 m
Let area of the square plot be A(1) and area of the square plot including the path be A(2)
Area can be calculated as, A(1) = x*x Meter Sqr
and A(2) = x'*x' = (x+6)*(x+6)
= (x+6)^2
= x^2+36+12x
Area of path = Area of Square plot including path - Area of square plot
= A(2) -A(1)
= x^2+36+12x - x^2
132 = 36+12x
12x = 132-36
12x = 96
x = 8
Thus, area of the plot = x*x = 8*8 = 64 Meter Sqr
Let the side of the square plot including the path be x' m
x' can be calculated by adding width of the path
Thus, x' = x+3+3 m
Let area of the square plot be A(1) and area of the square plot including the path be A(2)
Area can be calculated as, A(1) = x*x Meter Sqr
and A(2) = x'*x' = (x+6)*(x+6)
= (x+6)^2
= x^2+36+12x
Area of path = Area of Square plot including path - Area of square plot
= A(2) -A(1)
= x^2+36+12x - x^2
132 = 36+12x
12x = 132-36
12x = 96
x = 8
Thus, area of the plot = x*x = 8*8 = 64 Meter Sqr
Answered by
93
Let the side of the inner square measure Xm then its area will be X ×X=X^2
Since the path is 3m wide, then the side of the outer square =X+3+3=(X+6)m
Its area =(X+6) × (X+6)=X^2+12X+36
The area of the path =Area of outer square - Area of inner square =132m2
X^2 +12X +36-X^2=132m2
12X+36=132
12X=132-36
12X=96
X=8M
Length of the plot =8m
Area of the plot=8×8=64m2
Since the path is 3m wide, then the side of the outer square =X+3+3=(X+6)m
Its area =(X+6) × (X+6)=X^2+12X+36
The area of the path =Area of outer square - Area of inner square =132m2
X^2 +12X +36-X^2=132m2
12X+36=132
12X=132-36
12X=96
X=8M
Length of the plot =8m
Area of the plot=8×8=64m2
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