Question

A square-shaped pit was dug out to a depth of 5m. The side of the square was 4m. The sand taken out was spread out in the form of a thick rectangular bed of thickness 12m and length 40m. What is the breadth of the sand bed?

Answer 1

Volume of the sand removed :5 *4*4 cu m = 80 cu m
Using volume conservation
Volume dug out =volume of the sand bed
80 =12*40*breadth
80/480 =breadth
Breadth =1/6 m

Answer 2

Answer: The breadth of the sand bed is $\frac{1}{6}$

Step-by-step explanation:

Since we have given that

Side of square shaped pit = 4 m

Height of square shaped pit = 5 m

Dimensions of the rectangular bed is given by

Length of rectangular bed = 40 m

Height of rectangular bed = 12 m

Let breadth of rectangular bed be 'b'.

Since the sand taken out was spread out in the form of a thick rectangular bed .

So, their volume must be same.

$\text{Volume of square-shaped pit=Volume of rectangular bed }\\\\4\times 4\times 5=12\times 40\times b\\\\\frac{80}{480}=b\\\\\frac{1}{6}\ m=b$

Hence, the breadth of the sand bed is $\frac{1}{6}$