Math, asked by Taybaa4091, 3 months ago

A square shaped tile has dimensions of 10cm.How many such tiles are required to cover a rectangular shaped hall having length 112cm and breadth 70cm.

Answers

Answered by Dhruv4886
0

The number of tiles required to cover the hall is 78.  

Given:

A square-shaped tile has dimensions of 10cm

The hall has a length of 112cm and a breadth of 70cm

To find:

Number of square shapes required to cover the hall

Solution:

Formula used:

Number of tiles = [ (Area of Hall) / (Area of small tile) ]  

Area of rectangle = Length × Breadth

Area of square = side²

Given Side of square shaped tile = 10 cm

By the given formulas

=> Area of square shaped tile = (10 cm)² = 100 cm²

Given the length of hall = 112cm and breadth = 70cm  

=> Area of hall = 112 cm × 70 cm = 7840 cm²

By the given formula,

Number of tiles = [ (Area of Hall) / (Area of small tile) ]  

= [7840 cm² ]/100 cm²

=  78.4 ≅ 78

Therefore,

The number of tiles required to cover the hall is 78.

#SPJ1

Answered by DevendraLal
0

The hall will require 78 tiles to be covered.

GIVEN: A square-shaped tile has dimensions of 10cm

The hall measures 112cm in length and 70cm in width.

TO FIND: Number of square shapes necessary to cover the hall

SOLUTION:

Number of tiles = [(Hall Area) / Small Tile Area]

Rectangle area = length x breadth

Given Side of square shaped tile = 10 cm

Square tile area = (10 cm2)2 = 100 cm2

Given the length of hall = 112cm and breadth = 70cm

Area of hall = 112 cm × 70 cm = 7840 cm²

As a result of the given formula,

Number of tiles = [ (Area of Hall) / (Area of small tile)]  

= [7840 cm²]/100 cm²

= 78.4

= 78

The hall will require 78 tiles to be covered.

#SPJ1

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