Question

A square tile is having side of length 15 centimetre. How much such tiles required to cover the square floor of bathroom of side 8 metre?

Answer 1

side of the square floor = 8m = 800 cm

$area \: of \: the \: square \: floor = 800 \times 800 \\ = 640000{cm}^{2}$

$area \: of \: one \: tile = 15 \times 15 \\ = 225 {cm}^{2}$

$no. \: of \: tiles \: = 640000 \div 225 \\ = 2844 \: tiles$

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Answer 2

Side of a square tile = 15 cm
= 15/ 100 m
( 1 m = 100 cm)

Area of tile = side ✖ Side
= 15 / 100 ✖ 15 / 100
= 225/10000

Now
Side of bathroom = 8 m
Area = side ✖ side
= 8 ✖ 8
= 64

Tiles required = Area of bathroom / Area of each tile

= 64 ./ 225/ 10000.
= 64 ✖ 10000 / 225
=2844.4 Tiles

So required no. of tiles = 2844.4 Tiles