Math, asked by mohitkumar35ff, 4 months ago

A square tile is having side of length 15 cm. How many such tiles would be
required to cover the square floor of a bathroom of side 3 m?

please answer fast
RIGHT ANSWER WILL BE MARKED AS BRAINLIST. ​

Answers

Answered by Anonymous
1

Step-by-step explanation:

Area of a square tile=side^2=15^2=225cm^2

Area of bathroom =side^2=3^2=9m^2=90000cm^2

Hence

Number of tiles=90000/225=400tiles


mohitkumar35ff: RIGHT answer bro
Answered by yashchaurasiya30
1

Answer:

Area of tile

\begin{gathered} = {a}^{2} \\ \\ = {15}^{2} \\ \\ \\ = 225 {cm}^{2} \end{gathered}

=a

2

=15

2

=225cm

2

\begin{gathered}area \: of \: bathroom = {a}^{2} \\ \\ = {300}^{2} \\ \\ \\ = 90000 {cm}^{2} \end{gathered}

areaofbathroom=a

2

=300

2

=90000cm

2

\begin{gathered}no \: of \: tiles = \frac{area \: of \: floor}{area \: of \: one \: tile} \\ \\ \\ = \frac{90000}{225} \\ \\ \\ = 400tiles \\ \\ \\ Thank You. < br / > < br / > Hope this will be helpful for you. \end{gathered}

nooftiles=

areaofonetile

areaoffloor

=

225

90000

=400tiles

ThankYou.<br/><br/>Hopethiswillbehelpfulforyou.

Thank You.

Hope this will be helpful for you.

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