Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle?

Answer 1

Answer:

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Explanation:

$centripetal \: acceleration(a) \: = \frac{ {v}^{2} }{r} \\ given \: \\ a = 0.43 \\ v = 0.51 \\ substitute \\ 0.43 = \frac{ {0.51}^{2} }{r} \\ r = \frac{ {0.51}^{2} }{0.43} \\ \\ r = 0.6m$

The radius of the circle is 0.6m