Question

A squre carpet of side 5 m is laid on the floor of a room of length 5m 50cm and breadth 6m. Find the area of floor that is not carpeted. ​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

Area of the floor that is not carpeted is 8m².

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Side of the Square carpet = 5 m

Length of the Rectangle = 5 m 50 cm

Breadth of the Rectangle = 6 m

To Find :

Area of floor that is not carpeted

Solution :

$\textbf{\small{\underline{Find the Area of the Rectangle -}}}$

The Length of the Rectangular floor is 5 m 50 cm. Convert it into meters.

$\longrightarrow$ 500 + 50 = 550 cm

$\longrightarrow$ 550/100 = 5.5 m

★ Area = $\boxed{\sf{Length \times Breadth}}$

$\longrightarrow$ 5.5 × 6

$\longrightarrow$ 33

Area of the floor is 33 sq.m

$\rule{300}{1.5}$

$\textbf{\small{\underline{Area covered by the Carpet - }}}$

To get the area covered by the carpet ; find the area of the square.

★ Area = $\boxed{\sf{Side \times Side}}$

$\longrightarrow$ 5 × 5

$\longrightarrow$ 25

Area covered by the Carpet is 25 sq.m

$\rule{300}{1.5}$

$\textbf{\small{\underline{Area of the floor which is not carpeted -}}}$

To get the Area of the floor that is not carpeted ; Subtract the area of carpet from the Area of floor.

Area of the Carpet = 25 m²

Area of the Rectangular Floor = 33m²

$\longrightarrow$ 33 - 25

$\longrightarrow$ 8

$\therefore$ Area of the floor that is not carpeted is 8m².

Answer 2

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

The area of remaining room = 8m²

$\mathfrak{\large{\underline{\underline{Explanation:-}}}}$

Given that :

Length of side of carpet = 5m

We know :

$\bigstar \; \boxed{\sf{Area\; of\;the\; carpet = Side\times Side}}$

Put the given values :

$\sf => 5^2\\\sf => 5\times 5\\\sf=>25 m^2$

Now :

Length of room => 5m  50 cm.

(5m 50 cm can written as 5.5 m)

Breadth => 6.

We know :

$\bigstar \; \boxed{\sf{Area\; of\;the\; Room = Length\times Side}}$

Put the given Values :

$\sf=>5.5 \times 6\\\sf=> 33 m^2$

Now :

We know that :

Area of remaining room after putting carpet :

$\bigstar\;\boxed{\sf{Area\;of\; the\; room- Area\; of\;the\;carpet.}}$

Put the Values :

$\sf=> 33 - 25\\\\\sf => 8m^2$

Therefore the area of remaining room = 8m^2.