Question

A standard car develops 40hp find the maximum speed the car can attain against a resitance of 20kgwt

Answer 1

I think question is ------> a standard car develops 40hp. find the maximum speed the car can attain against a resistance of 20 kgwt due to air and friction. given efficiency of the engine is 25℅.

solution :- efficiency of engine = 25%
so, power = 25 % of 40hp
= 25/100 × 40 = 10hp
= 10 × 746 watt [ as 1 hp = 746 watt]
= 7460 watt

use formula , P = F.v
where P is power , F is force and v is speed.

here, P = 7460 watt , F = 20kgwt = 200N
so, 7460 = 200 × v
v = 7460/200 = 37.3 m/s

hence, speed of the car is 37.3 m/s

Answer 2

Answer:

Explanation:

I hope it helps you