Question

a) State the commercial unit of electric energy

b) An electric refrigerator rated as 750 W
operates 8 hours per day. What is the cost of
the energy to operate it for the month of
August at Rs. 2.50 per kWh.​

Answer 1

Answer: A. The Commercial unit of electrical energy is Kilo -Watt Hour (kWh).

B. Rs. 15

Explanation:

B. Wattage = 750W

Hours used = 8 hrs

Units used = (Wattage * Hours) / 1000

= (750 * 8)/1000 kWh

= (6000/1000) kWh

= 6 kWh

According to question,

1 kWh = Rs. 2.50

6 kWh = Rs. ( 2.50 * 6)

            = Rs. 15

Answer 2

the answer of commercial unit is 15 kw

750

(750)(8)/1000

6000/100

1kwh=2.50(6)

15kwh