a stationary car is accelerated at the rate of 5m/s^2. the distance covered by the cr till it reaches a speed of 40m/s is....
a. 100 m
b. 120 m
c. 160 m
d. 200 m
Answers
Answered by
3
V² - U² = 2aS
40² - 0² = 2*5*S
1600 = 10*S
So, S = 1600/10 = 160.
Therefore, till it reaches the speed of 40m/s it covers 160 m.
Answered by
2
Given :
To Find:
The distance covered by the car till it reaches a speed of
Solution:
From equations of motion, we know the relation between final speed , initial speed , acceleration and distance is given below:
v² = u² + 2×a×s ...1)
On putting respective value in above equation:
40² = 0² + 2×5×s
1600 = 10×s
So
s = 160 m
So the distance covered by the car is 160 m.
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