Question

A stationary particle Explodes into Two particles of mass A and B. If the Two particles move in opposite directions with velocity 3 m/s and 4 m/s respectively (Just after the Explosion ) Then ratio of magnitude of Their Linear Momentum is

Options:
1. 3/4
2. 4/3
3. A/B
4. 1

Answer 1

Answer:

$\bold{\boxed{\frac{P_{A}}{P_{B}}=\frac{3A}{4B}}}$

Explanation:

GIVEN:-

• Two particle of Mass A & B
• With velocity 3m/s and 4m/s respectively.

NEED TO FIND:-

• Ratio of their linear momentum(P).

SOLUTION:-

we know that,

$P=mV$

1st Particle:

$P_{A}=A×3m/s$

$P_{A}=3Am/s$

2ns Particle:

$P_{B}=B×4m/s$

$P_{B}=4Bm/s$

RATIO:

$\frac{P_{A}}{P_{B}}=\frac{3A\:m/s}{4B\:m/s}$

$\bold{\boxed{\frac{P_{A}}{P_{B}}=\frac{3A}{4B}}}$

HOPE THAT HELPS!!