Question

a stationary sound wave has frequency 165 hz speed of sound in air is 330m/s then the distance between 2 consecutive nodes is

Answer 1

Given that,  

Frequency of sound wave is 165 Hz

Speed of sound in air is 330 m/s  

To find,  

The distance between 2 consecutive nodes.  

Solution,

The distance between two consecutive nodes is half of the wavelength. The speed of a wave is thus given by :

$v=f\lambda$

$v=f\dfrac{\lambda}{2}\\\\d=\dfrac{\lambda}{2}\\\\d=\dfrac{v}{2f}\\\\d=\dfrac{330}{2\times 165}\\\\d=1\ m$

So, the distance between 2 consecutive nodes is 1 m.

Learn more,

Nodes

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