A stationary wave is incident on rigid wall, then distance between wall and first antinode is ........... (its velocity is 36 m/s and frequency is 72 Hz)
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Explanation:
The stationary wave is incident on rigid wall thus function as pipe closed at one end.
It forms node at that end
v= 36m/s
n = 72 hz
lamda=v/n
=36/72
=1/2
Distance between node and antinode = lamda/4
=1/2×4
=1/8 or 0.125
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