Question

A steady current of 0.5 amperes was passed through an aqueous solution of silver nitrate
for 30 minutes (using platinum electrodes)

Answer 1

Answer:

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Explanation:

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Answer 2

The amount of silver that is deposited in the electrode is equal to 0.08mg

Explanation:

Given,

• The current is 0.5 ampere, show the charge which will be carried ,q in 30 minutes is 0.5x30x60= 900C

• The reaction taking place is
• Ag+ + e- ---------> Ag , hence there will gain of one electron in this reaction

• Z for this reaction is 1 since the valency for silver is equal to 1, molecular mass is M in case of silver is equal to 108.

• According to faradays law = m= q/Z •M•F = 900/ (108x96500)= 0.08mg

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