Question

A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second.

Answer 1

Answer :-

$n = 6.25\times10^{18}e^-$

Given:-

I = 1 A

T = 1 s

$e^- = 1.67 × 10^{-19}C$

To find :-

Number of electrons flows in 1 s.

Solution:-

Let the number of electrons flows in 1 s be n.

Then by using formula,

$\boxed{\sf{ I = \dfrac {ne^-}{T}}}$

Put the given value,

$n = \dfrac {1\times 1}{1.67\times10^{-19}}$

$n = 6.25\times10^{18}e^-$