a steady current of 1 ampere flows through a conductor calculate the number of electrons that flows through any section of the conductor 1 second
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current (i) = (number (n)× charge on electron (e))÷time
therefore i = ne ÷ t
by putting the value
1 = n × 1.6×10^-19 ÷1
n = 1 ÷ 1.6× 10^-19
n = 0.625×10^19
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