Question

if roots of the equation x2+kx+12=0 are in the ratio 1:3 then the value of k will be

Answer 1

Answer:

Let a and b be the two roots

then a + b = -k/1 = -k

a.b=12/1 = 12

It is given a/b = 1/3

b=3a

a.3a = 12

a^2 = 12/3=4

a = 2

b=6

a+b=-k

2+6=-k

8=-k

k=-8 Ans