Question

A Steady Current of 1 ampere flows through a conductor calculate the number of electrons that flows through any sections of the conductor in one second . Please give me my question very fast

Answer 1

HI,

Friend, ur answer is typed downstairs ;)

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First, basics ,'

1)Current is the rate of flow of charge ,

given by [ i = $\frac{dq}{dt}$ ]

2) Electron charge = 1.609 x $10^{-19}$ C

3) steady current means the current isn't varying with time ;

4) charge can flow through any crossection of a conductor , and tht includes the surface of the conductor.

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Now, coming to your prob,

current i = 1 A ;

and time = 1 s;

and you want to calculate the charge which has flown in a duration of 1 s ;

use simple integration ;

dq = i dt ;

$\int\limits^q_0 {} \, dq = i \int\limits^1_0 {} \, dt$

because q = n e { charge is always an integral multiple of 'e'}

we get

n e = 1 x 1

and n = the number of electrons flown ;

=> n = 1/e ;

=> n = 6.24 x 10$^{18}$ electrons

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Ps. enjoy ;)