Question

A Steady Current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second. (Charge of electron 1.6×10 ki power -19 coulomb).

Answer 1

we know the formula
$q = i \times t$
and also we know that
$q = ne \: \\ where \: e = 1.6 \times {10}^{ - 19} c \:$
so substituting we get
$n = i \times t \: \times \frac{1}{e } \\ we \: have \: \: n = \frac{1 \times 1}{1.6 \times {10}^{ - 19} } \\ n = 6.25 \times {10}^{18}$

Answer 2

As we know i = dq/dt

As steady current of 1 ampere flows

so in 1 second charge flows = 1 coulomb

As we know q = ne

So n = q/e = 1/1.6 × 10^ -19 = 625 × 10^ 16 electrons