Math, asked by ayushmadurwar07, 2 months ago

A Steam pipe 20 cm in diameter is protected with a covering 6 cm thick for which the thermal conductivity is k-0.0003 in steady state. Find the heat lost per 2 hours through 2 meters long pipe, if the surface of the pipe of the pipe is at 300°C and outer surface of the covering is at 50°C

Answers

Answered by prasadanisha
1

Answer:

Step-by-step explanation:

Amount of heat lost per hour is 137058.5707 cal

Answered by anirudhayadav393
1

Concept Introduction: Calorimetry is the basic concept of Heat and Thermodynamics.

Given:

We have been Given: Diameter of Steam pipe is

20cm

Thickness of insulation is

6cm

k =  - 3 \times  {10}^{ - 4}

Time is

2 \: hrs

Length of pipe

2m

Temperature of inner surface of pipe is

300 \: degrees \: celsius

Temperature of outer surface of pipe is

50 \: degrees \: celsius

To Find:

We have to Find: Find the heat lost per two hours.

Solution:

According to the problem,

r =  \frac{ ln( \frac{16}{10} ) }{2\pi \times k}

Therefore Heat lost is,

h =   \frac{ temp._{lost}}{r}

therefore, putting the values in place, we get,

h =  \frac{(300 - 50) \times 2\pi \times k}{ ln( \frac{16}{10} ) }  \\ h =  \frac{250 \times 6.28 \times 3 \times  {10}^{ - 4} }{0.47}  \\ h =  \frac{0.471}{0.47}  \\ h = 1.002 \: degree \: celsius \: per \: hour

therefore in Two hours it will be,

 h_{per \: 2 \: hrs} = 2 \times 1.002 = 2.004 \: degrees \: celsius \: per \: 2 \: hrs

Final Answer: Heat lost per two hours is

2.004 \: degree \: celsius \: per \: 2 \: hrs

#SPJ2

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