Question

A steamer,going down stream in a river, covers distance between two towns in 15 hours.coming back up stream,it covers this distance in 20 hours . The speed of water is 3km/hr. Find distance between two towns.

Answer 1

Solution:-

Let the Speed of steamer be x km/hr.

Distance b/w the town be y km.

=> Speed of boat in upstream=(x-3)km/h

=> Speed of boat in downstream =(x+3) km/h

A.T.Q.

For Downstream,

$= > \frac{y}{x + 3} = 15 \\ \\ = > y = 15(x + 3)............(1)$

For Upstream,

$= > \frac{y}{x - 3} = 20 \\ \\ = > y = 20(x - 3)$

Equating eq 1 and 2. we get,

20( x - 3) = 15 ( x +3)

=> 4(x-3) = 3( x + 3)

=> 4x - 12 = 3x +9

=> x = 21 km/hr.

Putting x = 21 in eq 1.

=> y = 15x + 45

=> y = 315 + 45 = 360 km.

Answer 2

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A steamer going downstream in a river covers the distance between two towns in 20 hour coming back upstream it covers this distance in 25 hours the speed of water is 4 km/h. find the distance between the two town.
:
Let s = speed of the boat in still water
then
(s-4) = speed upstream
and
(s+4) = speed downstream
;
Distance both ways is equal. Make a distance equation; Distance = Time * speed
Up distance = down distance
25(s-4)= 20(s+4)
:
25s - 100 = 20s + 80
25s - 20s = +100 + 80
5s = 180
s = 180/5
s = 36 mph
:
Find the distance:
Dist = time * speed
downstream: d = 20(36+4) = 800 mi
and
Upstream: d = 25(36-4) = 800 mi also

hope it helps you....

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