Question

A steel cable with a radius of 1.5 cm supports a chairlift at a ski area . If the maximum stress is not to exceed 10^8Nm^-2 , what is the maximum load the cable can support .​

Answer 1

$\huge\mathbb\red{SOLUTION~:-}$

Maximum load = Maximum stress × area of cross-section

→ $\huge\bold{10^8}$ πr²

→ $\huge\bold{10^8}$ × 22/7 × ( 1.5 × 10^-2 )²

→ 7.07 × 10⁴ N

 ⊂ヽ

　 ＼＼ Λ＿Λ

　　 ＼( ˘ω˘ )

　　　 >　⌒ヽ

　　　/ 　 へ＼

　　 /　　/　＼＼

　　 ﾚ　ノ　　 ヽ_つ

　　/　/

　 /　/|

　(　(ヽ

　|　|、＼

　| 丿 ＼ ⌒)

　| |　　) /

ノ ) Lﾉ

(_／

Answer 2

Answer:Radius of the steel cable, r=1.5 cm = 0.015 m

Maximum allowable stress = 10

8

N/m

2

Maximum stress =

Areaofcross−section

Maximumforce

​

Maximum force = Maximum stress × Area of cross-section

= 10

8

×π×(0.015)

2

= 7.065×10

4

N

Explanation: