Question

. A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 108 N m–2, what is the maximum load the cable can support?
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Answer 1

$\bold{Answer}$

Radius of steel cable,

r = 1.5 cm = 0.015 m

☞Max allowable stress

= 108 N m–2

$\bold{Maximum\: stress}$ =

Maximum force / Area of cross-section

∴$\bold{Maximum\: force}$ =

Maximum stress × Area of cross-section

= 108 × π (0.015)2

= 7.065 × 104 N

The cable can support the maximum load of $\bold{7.065 x 104N}$.

$\bold{Thanks}$

Answer 2

Solution:-

Given:-

Radius = 1.5 cm = 0.015m

Maximum Stress = 108N m-2

By the Formula,

Maximum Force = Maximum Stress × Cross Section Area

=> 108 * ( π r²)

=> 108 * 22/7 * (0.015)²

=> 734.76 N.

Hence,

The Cable can Support the maximum load of 734.76 N.