A steel rod of length 6.0 m and diameter 20 mm is fixed between two rigid supports. Determine the stress in the rod, when the temperature increased by 80^(@)C if ends do not yield. Take Y=2.0xx10^(5)kg//cm^(2) and alpha=12xx10^(-6)"per ".^(@)C.
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Δ T = 800C Δ L = L αΔ T = 6 × 12 × 10-6 × 80 = 57.6 × 10-4 m. = 5.76 mm A = π(102)10 = π × 10-4 m2 , L = 6 m
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Answer:
answer=1857
Explanation:
Δ T = 800C Δ L = L αΔ T = 6 × 12 × 10-6 × 80 = 57.6 × 10-4 m. = 5.76 mm A = π(102)10 = π × 10-4 m2 , L = 6 m
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